Wolfram alpha disagrees with the answer in question (b).
Wolfram alpha link to the solution
I have also worked out the example and got similar results to the answer in the second link above.
Am I missing something?
Wolfram alpha disagrees with the answer in question (b).
Wolfram alpha link to the solution
I have also worked out the example and got similar results to the answer in the second link above.
Am I missing something?
Hey @Nicolas_Hadjittoouli! Our answer is correct, but so is the one on Wolfram (sort of…)! Let me show you:
Wolfram’s eigenvectors are
I put the “tilde” (~) sign over those vectors because they aren’t normalized! After normalizing them, we get
So, at this stage, \vert v_1 \rangle matches what we have in the codebook. But \vert v_2 \rangle still looks a little different. Here’s what we can do to make it “look” like ours:
In the second line, I factored out the factor of i, which essentially acts like a global phase to the state. We can simply “do away” with the global phase and redefine \vert v_2 \rangle as
which is the answer that we have in the codebook.
So, two things to remember when finding eigenvectors:
Just to illustrate this with a more familiar-feeling example, the Pauli Y matrix
has eigenvalues / eigenvectors
and
Try factoring out factors of i and playing the same game that we did with the codebook example and you will find that they don’t affect the eigenequations!
Oh, right! I couldn’t see, how I could get there. I totally forgot about the normalization.
Thanks a lot for the help!
Thank you for posting here! I forget about normalizing every once and a while too